Directions: Read the following passage carefully and answer the questions…

2022

Directions: Read the following passage carefully and answer the questions given below.

p men can do a work in q days and q women can do the same work in p days. If 20 men & 16 women can do the work together, they can complete the whole work in 53⅓ days.

20 men & 24 women started working together and they did work for 0.6x days and y number of boys did the remaining work in 0.45x days. If the whole work is completed in x days by y number of boys, then find the value of x.

Answer: E. 40ConceptIn work problems, the work done by a group equals (number of workers) × (rate per worker) × (number of days). When two groups take the same total…

  1. A.

    28

  2. B.

    50

  3. C.

    45

  4. D.

    25

  5. E.

    40

Attempted by 11 students.

Show answer & explanation

Correct answer: E

Concept

In work problems, the work done by a group equals (number of workers) × (rate per worker) × (number of days). When two groups take the same total man-days to finish a job, one member of either group has the same daily rate. If a body of workers can finish the whole job alone in a known time, their combined daily output equals (total work) ÷ (that time), and any portion of the job they do over a sub-interval is that output multiplied by the sub-interval.

Application

  1. Equal rates: p men finish in q days and q women finish in p days, so each job needs the same man-days as woman-days. Hence one man and one woman do equal work per day; take that common rate as 1 unit/day.

  2. Find the total work: 20 men + 16 women = 36 workers, each 1 unit/day, so 36 units/day. They finish in 53⅓ = 160/3 days, so total work = 36 × 160/3 = 1920 units.

  3. First phase: 20 men + 24 women = 44 workers = 44 units/day, working for 0.6x days, do 44 × 0.6x = 26.4x units.

  4. Boys' rate: the boys can finish the whole 1920 units alone in x days, so together they do 1920/x units/day.

  5. Boys' phase: in 0.45x days the boys do (1920/x) × 0.45x = 864 units, and this equals the remaining work 1920 − 26.4x.

  6. Solve: 864 = 1920 − 26.4x ⇒ 26.4x = 1056 ⇒ x = 40.

Cross-check

With x = 40: first phase 26.4 × 40 = 1056 units; boys do 864 units; 1056 + 864 = 1920 units = the full job. The boys' alone-rate is 1920/40 = 48 units/day, and 48 × (0.45 × 40) = 48 × 18 = 864 units, confirming the split.

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