Statements: C > T = R < W ≤ S = A < E ≥ B Conclusions: I. S > C II. W < B

Concept: In statement-and-conclusion inequality puzzles, first combine every statement into one continuous chain of relations. A conclusion linking two elements follows ONLY if the chain gives an unbroken path between them. When two elements are each related only to a common third element — or to it from opposite directions — their mutual order cannot be fixed, so any conclusion asserting a definite relation between them is false.

Application: combine the statements into one chain and test each conclusion against it.

1. Combined chain: C > T = R < W ≤ S = A < E ≥ B.

2. Conclusion I (S > C): from C > T = R, C is greater than R; from R < W ≤ S, S is also greater than R. Both C and S individually exceed R, but the chain has no direct link between C and S themselves, so their order cannot be fixed — Conclusion I does not follow.

3. Conclusion II (W < B): from W ≤ S = A, W is at most A; from A < E ≥ B, A and B are each compared only to E, from opposite directions, so A and B cannot be directly compared — and neither can W and B. Conclusion II does not follow.

Cross-check: assign values consistent with every statement — T = R = 5, C = 10, W = 6, S = 6, A = 6, E = 7, B = 1 — which satisfies 10 > 5 = 5 < 6 ≤ 6 = 6 < 7 ≥ 1. Here S (6) is not greater than C (10), and W (6) is not less than B (1); a different valid assignment can make either relation flip the other way. This confirms both conclusions are indeterminate, not guaranteed.

Since neither conclusion is forced by the combined chain, the correct choice is that neither conclusion is true.