What is the total swap time (Swap in & Swap out) in a system for a 15 MB…
2025
What is the total swap time (Swap in & Swap out) in a system for a 15 MB process with a transfer rate of 30 MBps. Given that there is an average latency of 12 ms, however no head seeks involved.
Answer: A. 1.024 sec — Solution: Compute transfer time for one direction: 15 MB ÷ 30 MB/s = 0.5 s There are two transfers (swap out and swap in), so total data transfer time = 0.5 s…
- A.
1.024 sec
- B.
1.00 sec
- C.
0.512 sec
- D.
12 sec
Attempted by 92 students.
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Correct answer: A
Solution:
Compute transfer time for one direction: 15 MB ÷ 30 MB/s = 0.5 s
There are two transfers (swap out and swap in), so total data transfer time = 0.5 s × 2 = 1.0 s
Latency: 12 ms per transfer → total latency = 12 ms × 2 = 24 ms = 0.024 s
Total swap time = data transfer time + total latency = 1.0 s + 0.024 s = 1.024 s
Final answer: 1.024 seconds
Note: No head-seek time is included, as stated in the problem.
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