Given below are two statements based on the following: A car travels 25…

2022

Given below are two statements based on the following:

A car travels 25 km/hour faster than a bus for a journey of 500 km, and the bus takes 10 hours more than the car.

Statement I: Speed of the car is 45 km/hour.

Statement II: Speed of the bus is 20 km/hour.

Choose the correct answer from the options given below:

Answer: B. Both Statement I and Statement II are falseConceptFor a fixed distance D, travel time is D/v. If the slower speed is x and the faster speed is x + d, a stated time difference Δt gives D/x − D/(x + d) =…

  1. A.

    Both Statement I and Statement II are true

  2. B.

    Both Statement I and Statement II are false

  3. C.

    Statement I is true but Statement II is false

  4. D.

    Statement I is false but Statement II is true

Attempted by 2 students.

Show answer & explanation

Correct answer: B

Concept

For a fixed distance D, travel time is D/v. If the slower speed is x and the faster speed is x + d, a stated time difference Δt gives D/x − D/(x + d) = Δt.

Only a positive speed is physically meaningful. After solving, substitute the speeds into both the speed-difference and time-difference conditions.

Application

  1. Let the bus speed be x km/h; then the car speed is x + 25 km/h.

  2. Using time = distance/speed, the bus time is 500/x hours and the car time is 500/(x + 25) hours.

  3. The bus takes 10 hours more, so 500/x − 500/(x + 25) = 10.

  4. Combining the fractions gives 12500/[x(x + 25)] = 10, hence x(x + 25) = 1250.

  5. Therefore x2 + 25x − 1250 = 0 = (x − 25)(x + 50). The positive root is x = 25.

  6. Thus the bus speed is 25 km/h and the car speed is 50 km/h. Statement I gives 45 km/h and Statement II gives 20 km/h, so neither statement matches the derived speeds.

Cross-check

  • Speed difference: 50 − 25 = 25 km/h.

  • Time difference: 500/25 − 500/50 = 20 − 10 = 10 hours.

Therefore, both Statement I and Statement II are false.

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