According to DeMorgan's theorem:
2016
According to DeMorgan's theorem:
Answer: D. a NAND gate is equivalent to negative-OR (inverted OR) gate — Correct Answer: Option D.According to DeMorgan's theorem: (A · B)′ = A′ + B′ and (A + B)′ = A′ · B′ A NAND gate performs the operation (A · B)′. Using…
- A.
a NAND gate is equivalent to negative-AND (inverted AND) gate
- B.
a NOR gate is equivalent to negative-OR (inverted OR) gate
- C.
a NAND gate is equivalent to NOR gate
- D.
a NAND gate is equivalent to negative-OR (inverted OR) gate
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Correct answer: D
Correct Answer: Option D.
According to DeMorgan's theorem:
(A · B)′ = A′ + B′
and
(A + B)′ = A′ · B′
A NAND gate performs the operation (A · B)′.
Using DeMorgan's theorem:
(A · B)′ = A′ + B′
This means the NAND operation is equivalent to first inverting both inputs and then applying OR. Therefore, a NAND gate is equivalent to a negative-OR gate, also called an inverted-input OR gate.
Similarly, a NOR gate is equivalent to a negative-AND gate.
Correct Answer: Option D.