The following table shows the number of students admitted (A) and left (L)…
2022
The following table shows the number of students admitted (A) and left (L) from the five different colleges (P-T) during the years 2016-2021. Year of foundation of all the five colleges is 2016. Based on the data in the table, answer the questions 1-5:
Year-wise Distribution of Students
Year | P A | P L | Q A | Q L | R A | R L | S A | S L | T A | T L |
|---|---|---|---|---|---|---|---|---|---|---|
2016 | 2250 | - | 2100 | - | 2400 | - | 3200 | - | 3100 | - |
2017 | 660 | 440 | 900 | 500 | 840 | 460 | 880 | 500 | 700 | 450 |
2018 | 580 | 420 | 650 | 430 | 800 | 500 | 800 | 520 | 760 | 460 |
2019 | 690 | 400 | 570 | 420 | 720 | 450 | 790 | 440 | 820 | 440 |
2020 | 760 | 500 | 600 | 380 | 680 | 480 | 840 | 450 | 880 | 420 |
2021 | 700 | 460 | 680 | 440 | 820 | 560 | 920 | 480 | 850 | 430 |
If M and N represent the number of students admitted in colleges S and Q from 2017 to 2021 respectively, then M-N =
Answer: A. 830 — CONCEPTWhen a variable represents a total over a period, add every relevant yearly value exactly once. For two totals M and N, their difference can be found…
- A.
830
- B.
790
- C.
870
- D.
770
Attempted by 1 students.
Show answer & explanation
Correct answer: A
CONCEPT
When a variable represents a total over a period, add every relevant yearly value exactly once. For two totals M and N, their difference can be found either by subtracting the totals or by summing the year-wise differences.
Both methods must agree; this agreement checks the arithmetic and confirms that all required years were included.
APPLICATION
For college S, M = 880 + 800 + 790 + 840 + 920 = 4,230.
For college Q, N = 900 + 650 + 570 + 600 + 680 = 3,400.
Therefore, M - N = 4,230 - 3,400 = 830.
CROSS-CHECK
Year by year, S - Q equals -20, 150, 220, 240, and 240. Their sum is -20 + 150 + 220 + 240 + 240 = 830, which confirms the result.
Hence, M - N = 830.