There are three numbers in the ratio of 3:5:7 and the sum of these numbers is…

2022

There are three numbers in the ratio of 3:5:7 and the sum of these numbers is 975. Find the three numbers.

Answer: A. 195, 325, 455ConceptIn a ratio a:b:c, write the quantities as ax, bx, and cx. Their total is (a+b+c)x, so one ratio part equals the total divided by a+b+c. ApplicationLet…

  1. A.

    195, 325, 455

  2. B.

    325, 195, 455

  3. C.

    195, 310, 470

  4. D.

    205, 315, 455

Attempted by 15 students.

Show answer & explanation

Correct answer: A

Concept

In a ratio a:b:c, write the quantities as ax, bx, and cx. Their total is (a+b+c)x, so one ratio part equals the total divided by a+b+c.

Application

  1. Let the three numbers be 3x, 5x, and 7x.

  2. Their sum gives 3x + 5x + 7x = 975, so 15x = 975.

  3. Therefore x = 975 / 15 = 65.

  4. The numbers are 3×65 = 195, 5×65 = 325, and 7×65 = 455.

Cross-check

Their sum is 195 + 325 + 455 = 975, and dividing all three numbers by 65 gives 3:5:7.

Result

Hence, the three numbers are 195, 325, and 455.

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