Match List I with List II: List I (Number Series) List II (Value of P) A. 2,…
2022
Match List I with List II:
List I (Number Series) | List II (Value of P) |
|---|---|
A. 2, 9, 28, 65, 126, P, ... | I. 220 |
B. 2, 10, 30, 68, 130, P, ... | II. 222 |
C. 3, 4, 11, 30, 67, 128, P, ... | III. 217 |
D. 5, 12, 31, 68, 129, P, ... | IV. 219 |
Choose the correct answer from the options given below:
Answer: C. A-III, B-II, C-IV, D-I — CONCEPTA number series can often be identified by expressing its nth term as a familiar sequence, such as consecutive cubes, plus a constant or a simple…
- A.
A-II, B-I, C-IV, D-III
- B.
A-IV, B-II, C-III, D-I
- C.
A-III, B-II, C-IV, D-I
- D.
A-I, B-II, C-IV, D-III
Attempted by 4 students.
Show answer & explanation
Correct answer: C
CONCEPT
A number series can often be identified by expressing its nth term as a familiar sequence, such as consecutive cubes, plus a constant or a simple function of n.
After identifying the rule, substitute the next index and match the resulting value with the second list.
APPLICATION
For A, the terms follow an = n3 + 1: 13 + 1 = 2, 23 + 1 = 9, and so on. Therefore the sixth term is 63 + 1 = 217.
For B, the terms follow an = n3 + n. Therefore the sixth term is 63 + 6 = 222.
For C, index the first term with n = 0. The rule is an = n3 + 3: 03 + 3 = 3 and 53 + 3 = 128. Therefore the next term is 63 + 3 = 219.
For D, the terms follow an = n3 + 4. Therefore the sixth term is 63 + 4 = 220.
CROSS-CHECK
The four computed values are distinct and exhaust List II: A gives 217, B gives 222, C gives 219, and D gives 220.
Series | Rule | Next value |
|---|---|---|
A | an = n3 + 1 | 217 |
B | an = n3 + n | 222 |
C | an = n3 + 3; n starts at 0 | 219 |
D | an = n3 + 4 | 220 |
RESULT
Therefore, the value mapping is A = 217, B = 222, C = 219, and D = 220.